[00:35] *** ambigu0us has joined #devious [00:55] *** cube_ has left "Leaving" [00:56] *** tydeas has joined #devious [02:17] *** dxtr has joined #devious [02:17] *** ChanServ sets mode: +v dxtr [02:42] *** dxtr has quit IRC (Ping timeout: 260 seconds) [02:43] *** cachopo has quit IRC (Read error: Connection reset by peer) [02:43] *** hjst has joined #devious [03:44] *** AmberJ_ has joined #devious [03:44] *** AmberJ_ has quit IRC (Changing host) [03:44] *** AmberJ_ has joined #devious [03:44] *** ChanServ sets mode: +v AmberJ_ [04:02] Off to werk [04:02] *whoosh* [04:02] Bye benDos! [04:02] *** benDos has quit IRC (Quit: Leaving) [04:07] *** benDossBot has quit IRC (Remote host closed the connection) [04:12] *** niteye has joined #devious [04:12] *** ChanServ sets mode: +v niteye [04:15] anyone has good guide on getting rid of horrible sister [04:17] niteye, YahooAnswers come to rescue: http://answers.yahoo.com/question/index?qid=20061113165954AAOqM58 :P [04:19] oh yahoo answers, is there anything you can't help us with? [04:20] the problem is my sister is older and inhumanly annoying, one of the answers suggests giving her money to go away, which might work considering how moneygreedy she is but i dont want to do that [04:20] in the meantime, time to check on my pizza [04:31] bbl [04:31] *** AmberJ_ has quit IRC (Quit: Leaving) [05:13] who loves ssh key auth... Kusuriya loves SSH key auth [05:14] *** benDos has joined #devious [05:14] *** ChanServ sets mode: +v benDos [05:14] Herro =D [05:14] herro [05:15] I just demo'd my compiler milestone one for a second time after i restarted [05:15] Passed my demo on the first shot [05:15] Yussss [05:15] score [05:15] im generating an 8196 bit SSH key [05:15] Seriously, it's due in like two weeks [05:15] Is that supposed to be weird? [05:15] its a lil large [05:15] I mean it's longish but not totally unreasonable [05:16] yeah [05:16] Well within the key length for a cert where to the user it will take about as long as 1024 [05:16] is it wrong to dream about openvpn ? [05:16] nope [05:16] I was considering lengthening my key for the sake of ssh'ing from potentially hostile airport wifi [05:16] niteye, i dream in regex brah [05:17] i was using it and then realised that there was no encryption so it was pointless [05:17] Wut [05:17] in my dream [05:17] Oooh [05:17] That makes more sense [05:18] as much sense as dreams can make [05:18] they could make an inception spinoff based on IT stuff [05:18] "you think they will be able to snoop on us" [05:18] "yeah, we need to go deeper" [05:18] s/IT stuff/onion routing [05:18] "yeah, we need to go deeper" [05:19] "a passworded RAR inside an SFTP thats inside a VPN thats encrypted with ipsec [05:19] we need to store deeper [05:19] a raid 5 in a raid 10 in a raid 01 in a raid 0 in a raid 1 [05:19] kusuriya, all driving a ipv6 location vb gui [05:20] and then the CSI team, "ill make a visual basic interface, see if i can trace their IP" [05:20] connecting to a couchDB stored in an SQLite db [05:20] Obviously all of this running in Debian/HURB [05:20] HURD* [05:20] yep [05:21] My goodness [05:21] GIMP depends on fortran? [05:21] some of the plugins [05:21] TIL [05:22] I think i need to eat less bagels [05:22] some of the visual filters you can write fortran to adjust how it acts [05:22] and yes [05:22] I've been havint them for breakfast too often [05:22] But they are so good, at cost me like $6/12 [05:22] 1 bagel is like 4 servings of bread [05:22] Delicious starchy goodness [05:22] but sooooooo unhealthy for you [05:22] That is slowly killing me [05:23] OH MY GOD GAIZ [05:23] FEDORA 17 UPGRADES TO GIMP 2.8 [05:23] :o [05:23] FANCY NEW SPLASH SCREEEN [05:23] AWEEEEEE EYYEEEAAAAHHH [05:23] I bet this has all the knobs. [05:23] that crashes a few seconds after run [05:24] Only if you forget to keep inserting the punch cards [05:27] its not scan cards by now? [05:28] Obviously you're not familiar with how open sauce works [05:28] you know why open sauce will not make it big? [05:29] ever eaten a sauce that a whole class of fifth graders tried to make together ? [05:29] compare that to the sauce mcdonalds makes [05:29] sure the sauce of mcdonalds is bloated and fat [05:30] and occasionally someone dies [05:30] but the taste omg, it just goes down tm [05:31] benDos: 2.8 is actually pretty nice, I have been using it for a while now [05:32] niteye: ive eaten the sauce made by a home ec class of 7th graders [05:32] it was pretty nummy [05:33] no matter how good it smells, im not touching sauce made by 7th graders who dont wash their hands after peeing on their fingers and have snot boogers falling into their egg yolk [05:33] niteye: that is still probably better than mcdonalds [05:33] i H9 mcdonalds [05:33] ignorance is bliss [05:34] niteye: youve never seen a homeec class have you [05:34] ive seen it in south park [05:34] lol [05:34] i assure you its 900000 times cleaner than mcds could hope to be [05:34] what about japanese mcdonalds ? [05:35] even japanese mcds are dirty [05:35] :-( [05:35] they have a standard for dirt, its mcdonalds [05:37] lenka is so cute [05:46] zod000, i haven't noticed any real changes yet [05:46] some new dialog boxes 'bout it [05:50] benDos: the previous version was crashy in w7 64bit, 2.8 isn't [05:50] *** mcchunkie has quit IRC (Remote host closed the connection) [05:54] gimp, as with most gtk3 programs, is like 999x better on a linux de with native gtk [05:54] Mostly since gtk is already sitting in my memory [05:54] CAUSE SHARED LIBS ARE LOVELY KYL [05:55] agreed, but there is a constant battling for photoshop licenses here, and I don't need or want photoshop enough to participate [05:55] and gtk on windows is surprisingly decent these days [05:57] Idk gimp has everything i want from a photo editor these days [05:57] The UI may be irritating but not nearly as irritating as paying retail for ps [05:58] Lol I enabled chrome dev tools on my work pc on gmail to grab an image that was hidden with some css magics [05:58] nearly crashed the computer :x [06:00] weird, i've never had that problem [06:00] yeah gimp does everything i need [06:00] benDos: Too bad even the prettiest splash screen in the world can't hide fedora's suck [06:00] the interface is better than it used to be [06:00] so who here is good at trig [06:00] I have a problem that I'm still not sure is solvable [06:01] 1+1=6? [06:01] jrick, i'll take a stab at it [06:02] zod000, enabling chrome dev tools eats ram hard [06:02] I'm on my work pc which barely has any ram at all, some old pentium d and a ton of "enterprise" network services av scanning AD, etc [06:03] well I have 3 beacons in a line separated by equal distances. I have a robot on one side of this line that's getting the angles from the first two beacons (A and B) and between the second two (B and C) [06:03] so that makes two non-right angle triangles that share a side [06:03] and I know one side length (the distance between the beacons, same for both triangles [06:04] and I need to find the other side lengths from each beacon to the robot [06:04] let me sketch that out for a sec [06:05] I tried using the law of cosines and got three equations, one for each smaller triangle and then the larger triangle (points Robot, A, and C) [06:05] but I suck at math and can't solve the system [06:06] it should work, I think, because I have three unknowns with those three equations (the three unknown side lengths) [06:06] wow... [06:07] Firefox dropped their old JS engine [06:07] and now its a ton better on memory [06:07] kusuriya, no they didn't [06:07] they added another pass [06:07] jrick, So what you really want is the distance from your robot to C [06:07] benDos: for fx18 they replaced it [06:07] since you already have the distance from your robot to A and B [06:07] benDos: yeah I need to find it's position in a cartesian plane [06:08] not saying iron monkey is any faster but fx seems to be better on memory now [06:11] benDos: if it makes you feel any better I threw it in matlab and it couldn't solve it :P [06:11] which worries me [06:12] That's because matlab is a BITCH [06:12] indeed [06:12] benDos: so wait, you use/write java at work, and don't have much ram? Seems like a recipe for failure [06:12] and wolfram alpha was all WTF how do I parse this? [06:13] jrick, sorry give me a sec at work [06:13] sure [06:17] zod000, work atm is my disability support services at my uni [06:17] :p [06:17] I have a few jobs atm [06:17] ah ok [06:17] jrick, maybe i'm getting this wrong [06:17] You have a line, with three points evenly spaces [06:18] And another point not on the line, the location of your robot [06:18] yes [06:18] You have the angle from point one to your robot, and point two [06:18] That gives you angle, side angle, and all of the sides and angles for that first triangle [06:18] You have that middle side since it is shared [06:19] and you have the opposing angle on point two [06:19] Then you have the known distance between points 2 and 3 [06:19] giving you side and angle [06:19] er [06:19] side angle side [06:19] and should give you that second triangle [06:19] right? [06:19] I don't have the side angle [06:19] only from A to Robot to B [06:19] and B to Robot to C [06:20] Oh ok let me fix up my sketch [06:21] halla [06:21] *** mcchunkie has joined #devious [06:21] *** ChanServ sets mode: +v mcchunkie [06:21] ohno [06:21] mathin [06:22] benDos: http://imgur.com/OBxZf [06:23] i have coworkers behind me [06:23] i trust you that it's sfw but i'm gonna play it safe while someone is faxing [06:23] Man i'm not so sure now [06:23] yes it's sfw [06:24] lol [06:24] it's math [06:24] clicked expecting boobies... got math [06:24] ok cool that matches my drawing now [06:24] #devious.. you have gone down hill [06:24] wait [06:24] you have the distance from R to the second point? [06:25] or that's just labeled in hopes that you'll get it later [06:25] right? [06:25] Ohhhh [06:25] no [06:25] only distances I know are d [06:25] between the beacons [06:25] ok let me match sure but i think you can do this [06:26] but once I get one of those other side lengths I can find a right triangle and get my distance from the line pretty easily [06:27] jrick is theta1+theta2=90? [06:28] it looks like it from your picture [06:28] no [06:28] dbtid, no^ [06:28] ok [06:28] jrick, give me a second [06:28] but i believe you can solve this with a SLE [06:28] are any of the values known? [06:28] d [06:28] there are no right triangles [06:28] there don't have to be right angles* [06:28] yeah [06:30] solve(theta1=d/a, theta2=d/a) [06:30] i believe [06:30] solve for a [06:30] theta1 = theta2? :) [06:31] where did that come from [06:31] So i'm doing tan(d/a)=theta1 and tan(d/a)=theta2 [06:31] but you're rig [06:31] hmm [06:31] s/but you're rig// [06:31] hmm [06:31] what are you trying to solve, exactly? [06:31] dbtid: need to find it's x,y position [06:31] you mean R? [06:32] benDos: that doesn't work without right angles I believe [06:32] dbtid: yep [06:32] teh robot [06:32] you know theta1 and theta2? [06:32] yes [06:32] jrick, i think you're right :/ [06:32] maybe [06:32] knowns are the theta1, theta2, and d [06:32] need to find any of b1, b2, or a [06:34] *** AmberJ_ has joined #devious [06:34] *** ChanServ sets mode: +v AmberJ_ [06:36] jrick, have you tried used the triangle RAC, cutting that into two right angle triangle [06:36] using that to get the line RA or RC [06:36] then go back [06:36] i think that's how i'd do it without fancy SLE's [06:36] I'm 99% sure that's how you solve this [06:38] hmm [06:38] i haven't yet [06:39] will try a bit later, im on my phone niw waiting for a bus [06:42] I wish android had a mosh client that didn't suck [06:42] what is the SLE acronym? [06:43] i talked with a friend here, who has a BS in Math, and a PhD in graphics [06:43] just looking at it [06:43] we see that you have a lot of information with law of since [06:43] but even then im still missing a distance arent i? [06:43] hold on [06:44] if c = len RA [06:44] if a = len RC [06:44] and r = len AC = 2d [06:44] write out the various law of sine equations for all three triangles [06:44] and go from there [06:44] you'll see there are a lot of relationships [06:45] you can get it down to a couple equations in a couple unknowns [06:45] then you may be able to do some elimination [06:45] dbtid, sle system of linear equations [06:45] if you know what i mean [06:45] jrick, really i'm 99% sure [06:46] do it my way with the cutting triangle RAC into two right triangles to get the length of RA or RC [06:46] ok [06:46] OK I'll try that [06:46] It isn't as pretty as "here's a matrix computer, solve it for me" [06:46] but you can probably reduce it to that once you hav eit working [06:47] are you talking about making 2 right triangles on the line AC going up to R? [06:48] Yup [06:48] You have the triangle RAC [06:48] then make a line from R perpendicular to AC [06:48] I know i've solved a very very similar problem like this before with that method [06:48] and this helps how? because you've just destroyed the fact that you know d and theta1 and theta2 [06:50] maybe if i make a right trisngle but kerp tge known side lengths [06:50] keep [06:50] dbtid, you can figure out the legths on the line [06:50] cause you can see where it intersects the line AC [06:50] the [06:50] then you have a right angle [06:50] that side, and theta [06:51] I've been wrong before [06:51] you don't have theta any more [06:51] you destroyed the angle at R [06:51] You do [06:51] I have other stuff doing atm but you can get it back [06:51] you have theta1+theta2 [06:51] the line R to some point on AC [06:52] I'm not claiming to be 100% certain, just that i've solved similar problems to this with that method [06:52] you just made them irrelevant, except that you have theta. but you don't know what the new angles are going to be when you draw that perpindicular line [06:52] hi dbtid [06:52] If you say so [06:52] howdy qbit [06:52] I disagree but i've doing a bunch of stuff atm so don't really have time to write out the proof [06:53] thing of how many angles you can make by moving R left and right, but making the line from R to AC perpindicular to AC [06:53] jrick: try #math :) [06:54] dbtid: Those angles would be the same [06:55] piroko, can you back me up here? [06:55] * benDos is pretty shit at math [06:55] I'm hyper cynical to anything dbtid says [06:55] also at work trying to get things done that aren't trig proofs [06:58] All I can back up is your claim about the perpendicular line maintaining the same angle on the opposing side no matter where you draw it [06:58] I just tested it [06:59] I believe i have a few page formal proof of the method sitting on my disk somewhere [07:00] ohshi it's quit'n time [07:00] later bros [07:00] cya, thanks for the help [07:00] np i'll log back in from home [07:01] 2 hour shift monday mornings :p [07:01] *** benDos has quit IRC (Quit: Leaving) [07:01] piroko: which angles are the same? [07:01] if you move R right and left on the line after dropping the perpindicular line, you'll still have a right angle, but those two interior angles will change [07:02] and theta1 and theta2 do not stay the same [07:02] you end up with a new theta1 and theta2 [07:02] Maybe I'm picturing this wrong. I only just joined lol [07:02] (this convo) [07:03] http://imgur.com/OBxZf [07:03] sfgw from jrick [07:03] his picture of the problem [07:03] *sfw [07:03] what jrick knows is d, theta1 and theta2, and obviously theta=theta1+theta2 [07:03] sfgw = Safe For Gone Wild [07:04] lol [07:04] this should be hawt [07:04] haha [07:04] what's gone wild? tv show or something? [07:04] * dbtid remembers Mutual of Omaha's Wild Kingdom [07:04] great show [07:04] And he's trying to find a and b1 and b2? [07:04] dbtid: it is a subreddit for naked people, think "Girls Gone Wild" from the infomercials [07:04] any one of those will help him figure out the rest [07:04] ohman, I think I got it? [07:04] zod000: interesting. the internet is a strange place [07:04] lemme see [07:05] yeah jrick? [07:05] dbtid: seeing naked women on the internet is far from strange, hell, it was a big factor in trying to get broadband when i was in college [07:05] lol [07:05] hmm [07:06] let me play with this for a little more [07:06] *** deuxenun_ has quit IRC (Read error: Connection reset by peer) [07:07] my exchange connection keeps going up and down, like a wack-a-mole [07:07] i suspect network jackassery [07:12] gorammit [07:12] thought I had a solution with 3 angles and no side lengths :( [07:13] hm maybe.. [07:20] *** tydeas has quit IRC (Quit: WeeChat 0.3.7) [07:23] *** cmeiklejohn has joined #devious [07:23] *** ChanServ sets mode: +o cmeiklejohn [07:30] *** tydeas has joined #devious [07:30] I think I solved it, b1 = 2*d*cos(theta1) [07:30] let me check [07:31] i'd like to see your derivation :) [07:33] New sets for macppc! [07:33] http://imgur.com/4gBk2 it's kind of fuzzy though [07:35] yeah i can't really make it out [07:39] guize http://imgur.com/gallery/yhEhQ [07:42] dbtid: so if I draw two right triangles like that, it results in a rectangle correct? [07:43] and I know my three angles for the inside triangles of that rectangle are theta1, theta2, and 90 degrees [07:44] jrick: i'm not sure i can read all that to make any sense of it [07:44] and my geometry is rusty too [07:44] and theta1 should be the same as angle A [07:44] same with theta2 and angle C [07:44] jrick: find a math tutor in a lab and ask? [07:44] yeah [07:45] i think some of your assumptions could be troublesome [07:45] i don't remember that you can just divide triangles down that way [07:55] hm yeah that's wrong [07:56] *** cmeiklejohn has quit IRC (Ping timeout: 255 seconds) [07:58] problem was angle A /= theta1 and angle C /= theta2 [07:59] I need to figure out how to find one of those other angles in the two bottom triangles [08:00] ohwait [08:00] nope nvm [08:01] lol [08:01] math tutor [08:01] hm, if you divide a triangle into two right triangles, are the angles where you drew the intersecting line at the point equal? [08:02] it looks like it [08:08] *** cmeiklejohn has joined #devious [08:08] *** ChanServ sets mode: +o cmeiklejohn [08:08] im watching a jap anime and the guy is hiding in a toilet, its got buttons and stuff, as if nearly every toilet is like that there [08:08] grr [08:09] ugh still doing this wrong [08:11] haha there is already a group trying to hammer out organic cannibis standards [08:14] TIL jrick fails at basic trig [08:14] lol [08:14] 08:12:50 < jrick> thought I had a solution with 3 angles and no side lengths :( [08:14] If you have all three angles, you have a triangle... [08:14] need a side length to solve it [08:15] (I might not have read the full context) [08:15] congruent triangles, and all that [08:15] TIL brycec fails at basic trig [08:16] niteye: Is there a such thing as a nonjap anime? [08:17] im wondering that too [08:17] but just in case, said its jap anyway [08:17] lol [08:19] *** Gallomimia has quit IRC (Ping timeout: 260 seconds) [08:19] moin [08:19] hi [08:19] * kusuriya wrings hands together [08:19] i should hear today or tomrrow if i get the house i have my eye on [08:20] Okay yeah I fail a bit. Assumed the problem was simple and stuff, hadn't read the backlog or looked at the problem. [08:20] Man trig was a long time ago... [08:20] I demand a resignation from the post of admin! :P [08:21] AmberJ_: you never were an admin, so there's nothing from which you can resign. [08:21] /ban b.r.y.c.e.c (for hilighting me :P) [08:21] ;) [08:22] Yes piroko and niteye there is non-jap anime. From a recent survey of sat/sunday morning cartoons, anime style is "in" but it's very westernized. [08:22] is there any death note related hentai out there ? [08:22] *** benDos has joined #devious [08:22] *** ChanServ sets mode: +v benDos [08:22] backish [08:22] niteye: see: rule34.net [08:22] or whatever it is [08:22] jrick, get that working yet? [08:22] wb benDos [08:22] thanks [08:23] s/wb/go away [08:23] thanks [08:23] :P [08:23] *** benDossBot has joined #devious [08:23] *** ChanServ sets mode: +v benDossBot [08:23] lazylopez_, doesn't do lookback you're thinking of benDossBot [08:23] Hai benDos =D [08:23] wb benDossBot [08:23] Thanks brycec [08:23] go away benDossBot [08:23] :P [08:24] go away AmberJ_ [08:24] :) [08:24] * AmberJ_ hides [08:24] before b.r.y.c.e.c bans him) [08:24] :P [08:24] *** ckrailo has joined #devious [08:24] *** ChanServ sets mode: +v ckrailo [08:25] s/^./fuuuuuuuuuu/ [08:25] fuuuuuuuuuuJOINS: ckrailo ( ckrailo!~ckrailo@208.86.167.247 ) [08:25] :D [08:25] looks like LL is broke again [08:25] s/broke/rich/ [08:25]